What are the solutions to the equation x^2+2x-300=0 ?

The solutions to the equation x^2+2x-300=0 are x=-1+sqrt(301),x=-1-sqrt(301)

Find the zeros of x^2+2x-300=0

The zeros of x^2+2x-300=0 are x=-1+sqrt(301),x=-1-sqrt(301)

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x^{2} + 2 x - 300 = 0

x = - 1 + 301, x = - 1 - 301

Decimal Notation

x = 16.34935 \dots, x = - 18.34935 \dots

Solution steps

x^{2} + 2 x - 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 300 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 300) = 2301

x_{1, 2} = \frac{- 2 \pm 2 301}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 301}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 301}{2 \cdot 1}

x = \frac{- 2 + 2 301}{2 \cdot 1} : - 1 + 301

x = \frac{- 2 - 2 301}{2 \cdot 1} : - 1 - 301

The solutions to the quadratic equation are:

x = - 1 + 301, x = - 1 - 301

x^{2} = 56 - x

\frac{3}{2} (4 x^{2} - 20 x + 60) = 0

x^{2} - 5 a + 8 x = 0

t, g (t - 1) = 5 - (t - 1)^{2}

x, f (x - 2) = x^{2} + 4 x + 7

What are the solutions to the equation x^2+2x-300=0 ?
The solutions to the equation x^2+2x-300=0 are x=-1+sqrt(301),x=-1-sqrt(301)
Find the zeros of x^2+2x-300=0
The zeros of x^2+2x-300=0 are x=-1+sqrt(301),x=-1-sqrt(301)