What are the solutions to the equation p^2-6p+5=0 ?

The solutions to the equation p^2-6p+5=0 are p=5,p=1

Find the zeros of p^2-6p+5=0

The zeros of p^2-6p+5=0 are p=5,p=1

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p^{2} - 6 p + 5 = 0

p = 5, p = 1

Solution steps

p^{2} - 6 p + 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

p_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, p_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

p = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

p = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

p = 5, p = 1

3 x^{2} + 25 = 0

- x^{2} + 10 x - 28

0 = x^{2} + 25

r^{2} - 12 r + 32 = 0

x, 0 = x^{2} + x - 12

What are the solutions to the equation p^2-6p+5=0 ?
The solutions to the equation p^2-6p+5=0 are p=5,p=1
Find the zeros of p^2-6p+5=0
The zeros of p^2-6p+5=0 are p=5,p=1