What are the solutions to the equation -x(-3x+1)+4=-6x ?

The solutions to the equation -x(-3x+1)+4=-6x are x=-5/6+i(sqrt(23))/6 ,x=-5/6-i(sqrt(23))/6

Find the zeros of -x(-3x+1)+4=-6x

The zeros of -x(-3x+1)+4=-6x are x=-5/6+i(sqrt(23))/6 ,x=-5/6-i(sqrt(23))/6

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- x (- 3 x + 1) + 4 = - 6 x

x = - \frac{5}{6} + i \frac{23}{6}, x = - \frac{5}{6} - i \frac{23}{6}

Solution steps

- x (- 3 x + 1) + 4 = - 6 x

Expand

- x (- 3 x + 1) + 4 : 3 x^{2} - x + 4

3 x^{2} - x + 4 = - 6 x

Move

6 x

to the left side

3 x^{2} + 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

Simplify

5^{2} - 4 \cdot 3 \cdot 4 : 23 i

x_{1, 2} = \frac{- 5 \pm 23 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 23 i}{2 \cdot 3}, x_{2} = \frac{- 5 - 23 i}{2 \cdot 3}

x = \frac{- 5 + 23 i}{2 \cdot 3} : - \frac{5}{6} + i \frac{23}{6}

x = \frac{- 5 - 23 i}{2 \cdot 3} : - \frac{5}{6} - i \frac{23}{6}

The solutions to the quadratic equation are:

x = - \frac{5}{6} + i \frac{23}{6}, x = - \frac{5}{6} - i \frac{23}{6}

- 6 x^{2} + x - 6 = - 8 x^{2}

(19 x - 2)^{2} - 2 (19 x - 2) - 8 = 0

y, z^{2} = 4 y^{2}

14 = 3 x - x^{2}

(\frac{7}{25})^{2} + y^{2} = 1

What are the solutions to the equation -x(-3x+1)+4=-6x ?
The solutions to the equation -x(-3x+1)+4=-6x are x=-5/6+i(sqrt(23))/6 ,x=-5/6-i(sqrt(23))/6
Find the zeros of -x(-3x+1)+4=-6x
The zeros of -x(-3x+1)+4=-6x are x=-5/6+i(sqrt(23))/6 ,x=-5/6-i(sqrt(23))/6