What are the solutions to the equation (19x-2)^2-2(19x-2)-8=0 ?

The solutions to the equation (19x-2)^2-2(19x-2)-8=0 are x= 6/19 ,x=0

Find the zeros of (19x-2)^2-2(19x-2)-8=0

The zeros of (19x-2)^2-2(19x-2)-8=0 are x= 6/19 ,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(19 x - 2)^{2} - 2 (19 x - 2) - 8 = 0

x = \frac{6}{19}, x = 0

Decimal Notation

x = 0.31578 \dots, x = 0

Solution steps

(19 x - 2)^{2} - 2 (19 x - 2) - 8 = 0

Expand

(19 x - 2)^{2} - 2 (19 x - 2) - 8 : 361 x^{2} - 114 x

361 x^{2} - 114 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 114 ) \pm ( - 114 ) ^{2} - 4 \cdot 361 \cdot 0}{2 \cdot 361}

(- 114)^{2} - 4 \cdot 361 \cdot 0 = 114

x_{1, 2} = \frac{- ( - 114 ) \pm 114}{2 \cdot 361}

Separate the solutions

x_{1} = \frac{- ( - 114 ) + 114}{2 \cdot 361}, x_{2} = \frac{- ( - 114 ) - 114}{2 \cdot 361}

x = \frac{- ( - 114 ) + 114}{2 \cdot 361} : \frac{6}{19}

x = \frac{- ( - 114 ) - 114}{2 \cdot 361} : 0

The solutions to the quadratic equation are:

x = \frac{6}{19}, x = 0

y, z^{2} = 4 y^{2}

14 = 3 x - x^{2}

(\frac{7}{25})^{2} + y^{2} = 1

x^{2} - 8 x + 1 = 0

k^{2} - 6 k + 5 = 0

What are the solutions to the equation (19x-2)^2-2(19x-2)-8=0 ?
The solutions to the equation (19x-2)^2-2(19x-2)-8=0 are x= 6/19 ,x=0
Find the zeros of (19x-2)^2-2(19x-2)-8=0
The zeros of (19x-2)^2-2(19x-2)-8=0 are x= 6/19 ,x=0