What are the solutions to the equation (5x+2)^2-12=0 ?

The solutions to the equation (5x+2)^2-12=0 are x=(2sqrt(3)-2)/5 ,x=(-2sqrt(3)-2)/5

Find the zeros of (5x+2)^2-12=0

The zeros of (5x+2)^2-12=0 are x=(2sqrt(3)-2)/5 ,x=(-2sqrt(3)-2)/5

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(5 x + 2)^{2} - 12 = 0

x = \frac{2 3 - 2}{5}, x = \frac{- 2 3 - 2}{5}

Decimal Notation

x = 0.29282 \dots, x = - 1.09282 \dots

Solution steps

(5 x + 2)^{2} - 12 = 0

Move

12

to the right side

(5 x + 2)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 2 = 12 : x = \frac{2 3 - 2}{5}

Solve

5 x + 2 = - 12 : x = \frac{- 2 3 - 2}{5}

The solutions to the quadratic equation are:

x = \frac{2 3 - 2}{5}, x = \frac{- 2 3 - 2}{5}

a^{2} - 12 a + 20 = 0

x^{2} + 2 x = - x + 4

(x - 4)^{2} - 13 = 0

x, x^{2} y y^{1} = e^{y}

10 x^{2} - 30 = - 20 x

What are the solutions to the equation (5x+2)^2-12=0 ?
The solutions to the equation (5x+2)^2-12=0 are x=(2sqrt(3)-2)/5 ,x=(-2sqrt(3)-2)/5
Find the zeros of (5x+2)^2-12=0
The zeros of (5x+2)^2-12=0 are x=(2sqrt(3)-2)/5 ,x=(-2sqrt(3)-2)/5