What are the solutions to the equation (y-3)^2-72=0 ?

The solutions to the equation (y-3)^2-72=0 are y=6sqrt(2)+3,y=-6sqrt(2)+3

Find the zeros of (y-3)^2-72=0

The zeros of (y-3)^2-72=0 are y=6sqrt(2)+3,y=-6sqrt(2)+3

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(y - 3)^{2} - 72 = 0

y = 62 + 3, y = - 62 + 3

Decimal Notation

y = 11.48528 \dots, y = - 5.48528 \dots

Solution steps

(y - 3)^{2} - 72 = 0

Move

72

to the right side

(y - 3)^{2} = 72

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 3 = 72 : y = 62 + 3

Solve

y - 3 = - 72 : y = - 62 + 3

The solutions to the quadratic equation are:

y = 62 + 3, y = - 62 + 3

2 x^{2} + 11 x + 6 = 0

2 x (x - 6) = 1

4 x^{2} - 15 x + 18 = 0

- 3 x^{2} + 36 x - 120 = - 15

33 z + 7 z^{2} = 10

What are the solutions to the equation (y-3)^2-72=0 ?
The solutions to the equation (y-3)^2-72=0 are y=6sqrt(2)+3,y=-6sqrt(2)+3
Find the zeros of (y-3)^2-72=0
The zeros of (y-3)^2-72=0 are y=6sqrt(2)+3,y=-6sqrt(2)+3