What are the solutions to the equation 7(x-3)^2-52=11 ?

The solutions to the equation 7(x-3)^2-52=11 are x=6,x=0

Find the zeros of 7(x-3)^2-52=11

The zeros of 7(x-3)^2-52=11 are x=6,x=0

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7 (x - 3)^{2} - 52 = 11

x = 6, x = 0

Solution steps

7 (x - 3)^{2} - 52 = 11

Move

52

to the right side

7 (x - 3)^{2} = 63

Divide both sides by

7

(x - 3)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 9 : x = 6

Solve

x - 3 = - 9 : x = 0

The solutions to the quadratic equation are:

x = 6, x = 0

2 (x - 4)^{2} + 7 = 13

(5 x - 11)^{2} + 6 = 150

x, y (x^{2} + 1) = 1

- x^{2} + 2 x + 63 = 0

3 u^{2} - 5 u - 2 = 0

What are the solutions to the equation 7(x-3)^2-52=11 ?
The solutions to the equation 7(x-3)^2-52=11 are x=6,x=0
Find the zeros of 7(x-3)^2-52=11
The zeros of 7(x-3)^2-52=11 are x=6,x=0