What are the solutions to the equation x^2-10x+61=0 ?

The solutions to the equation x^2-10x+61=0 are x=5+6i,x=5-6i

Find the zeros of x^2-10x+61=0

The zeros of x^2-10x+61=0 are x=5+6i,x=5-6i

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x^{2} - 10 x + 61 = 0

x = 5 + 6 i, x = 5 - 6 i

Solution steps

x^{2} - 10 x + 61 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 61}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 61 : 12 i

x_{1, 2} = \frac{- ( - 10 ) \pm 12 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 12 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 12 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 12 i}{2 \cdot 1} : 5 + 6 i

x = \frac{- ( - 10 ) - 12 i}{2 \cdot 1} : 5 - 6 i

The solutions to the quadratic equation are:

x = 5 + 6 i, x = 5 - 6 i

3 x^{2} + 6 x + 4 = 0

4 x + 3 > 15 or - 6 x \geq 12

\frac{2 x ^{- 2} y}{7 x ^{3} y ^{2}} \cdot \frac{14 x ^{5} y ^{3}}{x ^{0} y ^{5}}

x^{2} - 4 x - 1

7 x + 5 < - 9

What are the solutions to the equation x^2-10x+61=0 ?
The solutions to the equation x^2-10x+61=0 are x=5+6i,x=5-6i
Find the zeros of x^2-10x+61=0
The zeros of x^2-10x+61=0 are x=5+6i,x=5-6i