What are the solutions to the equation 25x^2-80x+64=0 ?

The solutions to the equation 25x^2-80x+64=0 are x= 8/5

Find the zeros of 25x^2-80x+64=0

The zeros of 25x^2-80x+64=0 are x= 8/5

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25 x^{2} - 80 x + 64 = 0

x = \frac{8}{5}

Decimal Notation

x = 1.6

Solution steps

25 x^{2} - 80 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 25 \cdot 64}{2 \cdot 25}

(- 80)^{2} - 4 \cdot 25 \cdot 64 = 0

x_{1, 2} = \frac{- ( - 80 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 80 )}{2 \cdot 25}

\frac{- ( - 80 )}{2 \cdot 25} = \frac{8}{5}

x = \frac{8}{5}

The solution to the quadratic equation is:

x = \frac{8}{5}

0 = 2 x^{2} - x - 6

a (x + 5) = x^{2} + 3 x - 10

2 x^{2} - 3 = 29

5 = (b + 1)^{2} + b^{2}

10 x^{2} + 3 x + 3 = 5

What are the solutions to the equation 25x^2-80x+64=0 ?
The solutions to the equation 25x^2-80x+64=0 are x= 8/5
Find the zeros of 25x^2-80x+64=0
The zeros of 25x^2-80x+64=0 are x= 8/5