What are the solutions to the equation 72-p=p^2 ?

The solutions to the equation 72-p=p^2 are p=8,p=-9

Find the zeros of 72-p=p^2

The zeros of 72-p=p^2 are p=8,p=-9

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72 - p = p^{2}

p = 8, p = - 9

Solution steps

72 - p = p^{2}

Switch sides

p^{2} = 72 - p

Move

p

to the left side

p^{2} + p = 72

Move

72

to the left side

p^{2} + p - 72 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 72) = 17

p_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 1 + 17}{2 \cdot 1}, p_{2} = \frac{- 1 - 17}{2 \cdot 1}

p = \frac{- 1 + 17}{2 \cdot 1} : 8

p = \frac{- 1 - 17}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

p = 8, p = - 9

2 x^{2} = - 2

8 x^{2} + 1 = 22 x + 1

4 (x + 3)^{2} = 25 (x - 2)^{2}

x, x^{2} - 6 x y + y^{2} = 0

x, 2 p x^{2} + 3 x - 2 - 5 p = 0

What are the solutions to the equation 72-p=p^2 ?
The solutions to the equation 72-p=p^2 are p=8,p=-9
Find the zeros of 72-p=p^2
The zeros of 72-p=p^2 are p=8,p=-9