What are the solutions to the equation 2m^2-15m+10=3m-m^2-5 ?

The solutions to the equation 2m^2-15m+10=3m-m^2-5 are m=5,m=1

Find the zeros of 2m^2-15m+10=3m-m^2-5

The zeros of 2m^2-15m+10=3m-m^2-5 are m=5,m=1

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2 m^{2} - 15 m + 10 = 3 m - m^{2} - 5

m = 5, m = 1

Solution steps

2 m^{2} - 15 m + 10 = 3 m - m^{2} - 5

Move

5

to the left side

2 m^{2} - 15 m + 15 = 3 m - m^{2}

Move

m^{2}

to the left side

3 m^{2} - 15 m + 15 = 3 m

Move

3 m

to the left side

3 m^{2} - 18 m + 15 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 15}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 15 = 12

m_{1, 2} = \frac{- ( - 18 ) \pm 12}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 18 ) + 12}{2 \cdot 3}, m_{2} = \frac{- ( - 18 ) - 12}{2 \cdot 3}

m = \frac{- ( - 18 ) + 12}{2 \cdot 3} : 5

m = \frac{- ( - 18 ) - 12}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

m = 5, m = 1

4 x^{2} + 18 x - 30 = 0

4 x = - 4 x^{2}

x^{2} - 2 x - 1 = 0

x, f (2 x + 1) = 1 - (x - 3)^{2}

x, 12 x^{2} = 3 x

What are the solutions to the equation 2m^2-15m+10=3m-m^2-5 ?
The solutions to the equation 2m^2-15m+10=3m-m^2-5 are m=5,m=1
Find the zeros of 2m^2-15m+10=3m-m^2-5
The zeros of 2m^2-15m+10=3m-m^2-5 are m=5,m=1