What are the solutions to the equation x^2+6x-35=0 ?

The solutions to the equation x^2+6x-35=0 are x=-3+2sqrt(11),x=-3-2sqrt(11)

Find the zeros of x^2+6x-35=0

The zeros of x^2+6x-35=0 are x=-3+2sqrt(11),x=-3-2sqrt(11)

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x^{2} + 6 x - 35 = 0

x = - 3 + 211, x = - 3 - 211

Decimal Notation

x = 3.63324 \dots, x = - 9.63324 \dots

Solution steps

x^{2} + 6 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 35) = 411

x_{1, 2} = \frac{- 6 \pm 4 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 11}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 11}{2 \cdot 1}

x = \frac{- 6 + 4 11}{2 \cdot 1} : - 3 + 211

x = \frac{- 6 - 4 11}{2 \cdot 1} : - 3 - 211

The solutions to the quadratic equation are:

x = - 3 + 211, x = - 3 - 211

x, (5 x + 8) (12 - 12 x) = 0

z^{2} + 5 z + 3 = 0

x, 2 x^{2} + 5 x - 8 = 0

4 x (x - 4) = 7

- 15 t^{2} + 2 = - 7 t

What are the solutions to the equation x^2+6x-35=0 ?
The solutions to the equation x^2+6x-35=0 are x=-3+2sqrt(11),x=-3-2sqrt(11)
Find the zeros of x^2+6x-35=0
The zeros of x^2+6x-35=0 are x=-3+2sqrt(11),x=-3-2sqrt(11)