What are the solutions to the equation completesquare 3x^2-x-2=1 ?

The solutions to the equation completesquare 3x^2-x-2=1 are x=(sqrt(37)+1)/6 ,x=(-sqrt(37)+1)/6

Find the zeros of completesquare 3x^2-x-2=1

The zeros of completesquare 3x^2-x-2=1 are x=(sqrt(37)+1)/6 ,x=(-sqrt(37)+1)/6

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3 x^{2} - x - 2 = 1

x = \frac{37 + 1}{6}, x = \frac{- 37 + 1}{6}

Decimal Notation

x = 1.18046 \dots, x = - 0.84712 \dots

Solution steps

3 x^{2} - x - 2 = 1

Move

2

to the right side

3 x^{2} - x = 3

Divide both sides by

3

\frac{3 x ^{2} - x}{3} = \frac{3}{3}

x^{2} - \frac{x}{3} = 1

Rewrite in the form

(x + a)^{2} = b

(x - \frac{1}{6})^{2} = \frac{37}{36}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{1}{6} = \frac{37}{36} : x = \frac{37 + 1}{6}

Solve

x - \frac{1}{6} = - \frac{37}{36} : x = \frac{- 37 + 1}{6}

The solutions to the quadratic equation are:

x = \frac{37 + 1}{6}, x = \frac{- 37 + 1}{6}

(x - 2)^{2} = 12

- x^{2} - 17 x + 53 = - 2 x^{2} + 3

y^{2} - 14 y = - 30

5 x^{2} + 7 = - 8

5 t^{2} - 60 t + 27 = 0

What are the solutions to the equation completesquare 3x^2-x-2=1 ?
The solutions to the equation completesquare 3x^2-x-2=1 are x=(sqrt(37)+1)/6 ,x=(-sqrt(37)+1)/6
Find the zeros of completesquare 3x^2-x-2=1
The zeros of completesquare 3x^2-x-2=1 are x=(sqrt(37)+1)/6 ,x=(-sqrt(37)+1)/6