What are the solutions to the equation -6-12n^2=-396 ?

The solutions to the equation -6-12n^2=-396 are n=sqrt(65/2),n=-sqrt(65/2)

Find the zeros of -6-12n^2=-396

The zeros of -6-12n^2=-396 are n=sqrt(65/2),n=-sqrt(65/2)

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- 6 - 12 n^{2} = - 396

n = \frac{65}{2}, n = - \frac{65}{2}

Decimal Notation

n = 5.70087 \dots, n = - 5.70087 \dots

Solution steps

- 6 - 12 n^{2} = - 396

Move

6

to the right side

- 12 n^{2} = - 390

Divide both sides by

- 12

n^{2} = \frac{65}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{65}{2}, n = - \frac{65}{2}

m^{2} + 4 m - 3 = 0

(7 + 2 x) (3 + 2 x) = 77

(3 x + 4)^{2} = 16 (3 x + 4)

x^{2} = 15 x - 36

x, f (x + 2) = 3 x^{2} + 2

What are the solutions to the equation -6-12n^2=-396 ?
The solutions to the equation -6-12n^2=-396 are n=sqrt(65/2),n=-sqrt(65/2)
Find the zeros of -6-12n^2=-396
The zeros of -6-12n^2=-396 are n=sqrt(65/2),n=-sqrt(65/2)