What are the solutions to the equation m^2+4m-3=0 ?

The solutions to the equation m^2+4m-3=0 are m=-2+sqrt(7),m=-2-sqrt(7)

Find the zeros of m^2+4m-3=0

The zeros of m^2+4m-3=0 are m=-2+sqrt(7),m=-2-sqrt(7)

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m^{2} + 4 m - 3 = 0

m = - 2 + 7, m = - 2 - 7

Decimal Notation

m = 0.64575 \dots, m = - 4.64575 \dots

Solution steps

m^{2} + 4 m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 3) = 27

m_{1, 2} = \frac{- 4 \pm 2 7}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 2 7}{2 \cdot 1}, m_{2} = \frac{- 4 - 2 7}{2 \cdot 1}

m = \frac{- 4 + 2 7}{2 \cdot 1} : - 2 + 7

m = \frac{- 4 - 2 7}{2 \cdot 1} : - 2 - 7

The solutions to the quadratic equation are:

m = - 2 + 7, m = - 2 - 7

(7 + 2 x) (3 + 2 x) = 77

(3 x + 4)^{2} = 16 (3 x + 4)

x^{2} = 15 x - 36

x, f (x + 2) = 3 x^{2} + 2

y, x - y^{2} = 4

What are the solutions to the equation m^2+4m-3=0 ?
The solutions to the equation m^2+4m-3=0 are m=-2+sqrt(7),m=-2-sqrt(7)
Find the zeros of m^2+4m-3=0
The zeros of m^2+4m-3=0 are m=-2+sqrt(7),m=-2-sqrt(7)