What are the solutions to the equation y^2+y^2=1 ?

The solutions to the equation y^2+y^2=1 are y= 1/(sqrt(2)),y=-1/(sqrt(2))

Find the zeros of y^2+y^2=1

The zeros of y^2+y^2=1 are y= 1/(sqrt(2)),y=-1/(sqrt(2))

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y^{2} + y^{2} = 1

y = \frac{1}{2}, y = - \frac{1}{2}

Decimal Notation

y = 0.70710 \dots, y = - 0.70710 \dots

Solution steps

y^{2} + y^{2} = 1

Add similar elements:

y^{2} + y^{2} = 2 y^{2}

2 y^{2} = 1

Divide both sides by

2

y^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{1}{2}, y = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

y = \frac{1}{2}, y = - \frac{1}{2}

w^{2} - 4 w - 3 = 0

x, f = u^{1} (x^{2})

400 - x^{2} = 60 x - 300

3 x^{2} + 11 x = - 5

x, x^{2} + x y + y^{2} - 3 = 0

What are the solutions to the equation y^2+y^2=1 ?
The solutions to the equation y^2+y^2=1 are y= 1/(sqrt(2)),y=-1/(sqrt(2))
Find the zeros of y^2+y^2=1
The zeros of y^2+y^2=1 are y= 1/(sqrt(2)),y=-1/(sqrt(2))