What are the solutions to the equation 3/5 x^2-x= 1/5 ?

The solutions to the equation 3/5 x^2-x= 1/5 are x=(5+sqrt(37))/6 ,x=(5-sqrt(37))/6

Find the zeros of 3/5 x^2-x= 1/5

The zeros of 3/5 x^2-x= 1/5 are x=(5+sqrt(37))/6 ,x=(5-sqrt(37))/6

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\frac{3}{5} x^{2} - x = \frac{1}{5}

x = \frac{5 + 37}{6}, x = \frac{5 - 37}{6}

Decimal Notation

x = 1.84712 \dots, x = - 0.18046 \dots

Solution steps

\frac{3}{5} x^{2} - x = \frac{1}{5}

Multiply both sides by

5

3 x^{2} - 5 x = 1

Move

1

to the left side

3 x^{2} - 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 1) = 37

x_{1, 2} = \frac{- ( - 5 ) \pm 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 37}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 37}{2 \cdot 3}

x = \frac{- ( - 5 ) + 37}{2 \cdot 3} : \frac{5 + 37}{6}

x = \frac{- ( - 5 ) - 37}{2 \cdot 3} : \frac{5 - 37}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 37}{6}, x = \frac{5 - 37}{6}

x^{2} + 1 0^{2} = 1 3^{2}

(x^{2} - 2 x + 3) = 0

- x^{2} + 4 x - 2 = 0

105 = x^{2} + 8 x

0 = 3 x^{2} - 9 x + 27

What are the solutions to the equation 3/5 x^2-x= 1/5 ?
The solutions to the equation 3/5 x^2-x= 1/5 are x=(5+sqrt(37))/6 ,x=(5-sqrt(37))/6
Find the zeros of 3/5 x^2-x= 1/5
The zeros of 3/5 x^2-x= 1/5 are x=(5+sqrt(37))/6 ,x=(5-sqrt(37))/6