What are the solutions to the equation (b-2x^2)/a =m ?

The solutions to the equation (b-2x^2)/a =m are x=isqrt((am-b)/2),x=-isqrt((am-b)/2);\quad a\ne 0

Find the zeros of (b-2x^2)/a =m

The zeros of (b-2x^2)/a =m are x=isqrt((am-b)/2),x=-isqrt((am-b)/2);\quad a\ne 0

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\frac{b - 2 x ^{2}}{a} = m

x = i \frac{am - b}{2}, x = - i \frac{am - b}{2}; a \neq = 0

Solution steps

\frac{b - 2 x ^{2}}{a} = m

Multiply both sides by

a

b - 2 x^{2} = ma; a \neq = 0

Move

b

to the right side

- 2 x^{2} = ma - b; a \neq = 0

Divide both sides by

- 2; a \neq = 0

x^{2} = - \frac{am - b}{2}; a \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{am - b}{2}, x = - - \frac{am - b}{2}; a \neq = 0

Simplify

- \frac{am - b}{2} : i \frac{am - b}{2}

Simplify

- - \frac{am - b}{2} : - i \frac{am - b}{2}

x = i \frac{am - b}{2}, x = - i \frac{am - b}{2}; a \neq = 0

(x + 9) + (x + 9)^{2} = 0

x^{2} - 7 x - 330 = 0

x, 0 = 4 x^{2} + y^{2}

x^{2} - 12 x = - 31

s^{2} + 2 s + 1.49

What are the solutions to the equation (b-2x^2)/a =m ?
The solutions to the equation (b-2x^2)/a =m are x=isqrt((am-b)/2),x=-isqrt((am-b)/2);\quad a\ne 0
Find the zeros of (b-2x^2)/a =m
The zeros of (b-2x^2)/a =m are x=isqrt((am-b)/2),x=-isqrt((am-b)/2);\quad a\ne 0