What are the solutions to the equation (x+9)+(x+9)^2=0 ?

The solutions to the equation (x+9)+(x+9)^2=0 are x=-9,x=-10

Find the zeros of (x+9)+(x+9)^2=0

The zeros of (x+9)+(x+9)^2=0 are x=-9,x=-10

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(x + 9) + (x + 9)^{2} = 0

x = - 9, x = - 10

Solution steps

(x + 9) + (x + 9)^{2} = 0

Expand

(x + 9) + (x + 9)^{2} : x^{2} + 19 x + 90

x^{2} + 19 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

1 9^{2} - 4 \cdot 1 \cdot 90 = 1

x_{1, 2} = \frac{- 19 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 19 + 1}{2 \cdot 1}, x_{2} = \frac{- 19 - 1}{2 \cdot 1}

x = \frac{- 19 + 1}{2 \cdot 1} : - 9

x = \frac{- 19 - 1}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 9, x = - 10

x^{2} - 7 x - 330 = 0

x, 0 = 4 x^{2} + y^{2}

x^{2} - 12 x = - 31

s^{2} + 2 s + 1.49

3 x^{2} + 39 = 0

What are the solutions to the equation (x+9)+(x+9)^2=0 ?
The solutions to the equation (x+9)+(x+9)^2=0 are x=-9,x=-10
Find the zeros of (x+9)+(x+9)^2=0
The zeros of (x+9)+(x+9)^2=0 are x=-9,x=-10