What are the solutions to the equation t^2+9t+3=-4t^2 ?

The solutions to the equation t^2+9t+3=-4t^2 are t=(-9+sqrt(21))/(10),t=(-9-sqrt(21))/(10)

Find the zeros of t^2+9t+3=-4t^2

The zeros of t^2+9t+3=-4t^2 are t=(-9+sqrt(21))/(10),t=(-9-sqrt(21))/(10)

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t^{2} + 9 t + 3 = - 4 t^{2}

t = \frac{- 9 + 21}{10}, t = \frac{- 9 - 21}{10}

Decimal Notation

t = - 0.44174 \dots, t = - 1.35825 \dots

Solution steps

t^{2} + 9 t + 3 = - 4 t^{2}

Move

4 t^{2}

to the left side

5 t^{2} + 9 t + 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

9^{2} - 4 \cdot 5 \cdot 3 = 21

t_{1, 2} = \frac{- 9 \pm 21}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- 9 + 21}{2 \cdot 5}, t_{2} = \frac{- 9 - 21}{2 \cdot 5}

t = \frac{- 9 + 21}{2 \cdot 5} : \frac{- 9 + 21}{10}

t = \frac{- 9 - 21}{2 \cdot 5} : \frac{- 9 - 21}{10}

The solutions to the quadratic equation are:

t = \frac{- 9 + 21}{10}, t = \frac{- 9 - 21}{10}

- 2 x^{2} + 36 x = 157

x^{2} - 4 x - 27 = 0

x^{2} + 8 x - 884 = 0

7 r^{2} - r - 4 = 6 r^{2}

p^{2} + 16 p - 4 = 0

What are the solutions to the equation t^2+9t+3=-4t^2 ?
The solutions to the equation t^2+9t+3=-4t^2 are t=(-9+sqrt(21))/(10),t=(-9-sqrt(21))/(10)
Find the zeros of t^2+9t+3=-4t^2
The zeros of t^2+9t+3=-4t^2 are t=(-9+sqrt(21))/(10),t=(-9-sqrt(21))/(10)