What are the solutions to the equation -2x^2+36x=157 ?

The solutions to the equation -2x^2+36x=157 are x=(18-sqrt(10))/2 ,x=(18+sqrt(10))/2

Find the zeros of -2x^2+36x=157

The zeros of -2x^2+36x=157 are x=(18-sqrt(10))/2 ,x=(18+sqrt(10))/2

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- 2 x^{2} + 36 x = 157

x = \frac{18 - 10}{2}, x = \frac{18 + 10}{2}

Decimal Notation

x = 7.41886 \dots, x = 10.58113 \dots

Solution steps

- 2 x^{2} + 36 x = 157

Move

157

to the left side

- 2 x^{2} + 36 x - 157 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 ( - 2 ) ( - 157 )}{2 ( - 2 )}

3 6^{2} - 4 (- 2) (- 157) = 210

x_{1, 2} = \frac{- 36 \pm 2 10}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 36 + 2 10}{2 ( - 2 )}, x_{2} = \frac{- 36 - 2 10}{2 ( - 2 )}

x = \frac{- 36 + 2 10}{2 ( - 2 )} : \frac{18 - 10}{2}

x = \frac{- 36 - 2 10}{2 ( - 2 )} : \frac{18 + 10}{2}

The solutions to the quadratic equation are:

x = \frac{18 - 10}{2}, x = \frac{18 + 10}{2}

x^{2} - 4 x - 27 = 0

x^{2} + 8 x - 884 = 0

7 r^{2} - r - 4 = 6 r^{2}

p^{2} + 16 p - 4 = 0

3 m^{2} - 4 m + 4 = 5

What are the solutions to the equation -2x^2+36x=157 ?
The solutions to the equation -2x^2+36x=157 are x=(18-sqrt(10))/2 ,x=(18+sqrt(10))/2
Find the zeros of -2x^2+36x=157
The zeros of -2x^2+36x=157 are x=(18-sqrt(10))/2 ,x=(18+sqrt(10))/2