What are the solutions to the equation 4x^2+7=-9x ?

The solutions to the equation 4x^2+7=-9x are x=-9/8+i(sqrt(31))/8 ,x=-9/8-i(sqrt(31))/8

Find the zeros of 4x^2+7=-9x

The zeros of 4x^2+7=-9x are x=-9/8+i(sqrt(31))/8 ,x=-9/8-i(sqrt(31))/8

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4 x^{2} + 7 = - 9 x

x = - \frac{9}{8} + i \frac{31}{8}, x = - \frac{9}{8} - i \frac{31}{8}

Solution steps

4 x^{2} + 7 = - 9 x

Move

9 x

to the left side

4 x^{2} + 7 + 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 9 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

Simplify

9^{2} - 4 \cdot 4 \cdot 7 : 31 i

x_{1, 2} = \frac{- 9 \pm 31 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 31 i}{2 \cdot 4}, x_{2} = \frac{- 9 - 31 i}{2 \cdot 4}

x = \frac{- 9 + 31 i}{2 \cdot 4} : - \frac{9}{8} + i \frac{31}{8}

x = \frac{- 9 - 31 i}{2 \cdot 4} : - \frac{9}{8} - i \frac{31}{8}

The solutions to the quadratic equation are:

x = - \frac{9}{8} + i \frac{31}{8}, x = - \frac{9}{8} - i \frac{31}{8}

π = - 50 + 32 q - 4 q^{2}

\frac{1}{3} (x + 4)^{2} - 1 = 5

- 2 x^{2} - 3 x + 9 = 0

x^{2} + 7 = 2 x

5 b^{2} - 36 b = 32

What are the solutions to the equation 4x^2+7=-9x ?
The solutions to the equation 4x^2+7=-9x are x=-9/8+i(sqrt(31))/8 ,x=-9/8-i(sqrt(31))/8
Find the zeros of 4x^2+7=-9x
The zeros of 4x^2+7=-9x are x=-9/8+i(sqrt(31))/8 ,x=-9/8-i(sqrt(31))/8