What are the solutions to the equation 9n^2-7n-4=0 ?

The solutions to the equation 9n^2-7n-4=0 are n=(7+sqrt(193))/(18),n=(7-sqrt(193))/(18)

Find the zeros of 9n^2-7n-4=0

The zeros of 9n^2-7n-4=0 are n=(7+sqrt(193))/(18),n=(7-sqrt(193))/(18)

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9 n^{2} - 7 n - 4 = 0

n = \frac{7 + 193}{18}, n = \frac{7 - 193}{18}

Decimal Notation

n = 1.16069 \dots, n = - 0.38291 \dots

Solution steps

9 n^{2} - 7 n - 4 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

(- 7)^{2} - 4 \cdot 9 (- 4) = 193

n_{1, 2} = \frac{- ( - 7 ) \pm 193}{2 \cdot 9}

Separate the solutions

n_{1} = \frac{- ( - 7 ) + 193}{2 \cdot 9}, n_{2} = \frac{- ( - 7 ) - 193}{2 \cdot 9}

n = \frac{- ( - 7 ) + 193}{2 \cdot 9} : \frac{7 + 193}{18}

n = \frac{- ( - 7 ) - 193}{2 \cdot 9} : \frac{7 - 193}{18}

The solutions to the quadratic equation are:

n = \frac{7 + 193}{18}, n = \frac{7 - 193}{18}

25 m^{2} + 36 m + 9 = 6 m

7 x^{2} + 19 x = 6

- 4 x^{2} + 800 x - 30000 = 0

x^{2} + (- 1)^{2} + 2 x + 4 (- 1) + 2 = 0

9 x^{2} = 121

What are the solutions to the equation 9n^2-7n-4=0 ?
The solutions to the equation 9n^2-7n-4=0 are n=(7+sqrt(193))/(18),n=(7-sqrt(193))/(18)
Find the zeros of 9n^2-7n-4=0
The zeros of 9n^2-7n-4=0 are n=(7+sqrt(193))/(18),n=(7-sqrt(193))/(18)