What are the solutions to the equation 4x^2+6x+35=16x^2+7x ?

The solutions to the equation 4x^2+6x+35=16x^2+7x are x=-7/4 ,x= 5/3

Find the zeros of 4x^2+6x+35=16x^2+7x

The zeros of 4x^2+6x+35=16x^2+7x are x=-7/4 ,x= 5/3

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4 x^{2} + 6 x + 35 = 16 x^{2} + 7 x

x = - \frac{7}{4}, x = \frac{5}{3}

Decimal Notation

x = - 1.75, x = 1.66666 \dots

Solution steps

4 x^{2} + 6 x + 35 = 16 x^{2} + 7 x

Move

7 x

to the left side

4 x^{2} - x + 35 = 16 x^{2}

Move

16 x^{2}

to the left side

- 12 x^{2} - x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 12 ) \cdot 35}{2 ( - 12 )}

(- 1)^{2} - 4 (- 12) \cdot 35 = 41

x_{1, 2} = \frac{- ( - 1 ) \pm 41}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 41}{2 ( - 12 )}, x_{2} = \frac{- ( - 1 ) - 41}{2 ( - 12 )}

x = \frac{- ( - 1 ) + 41}{2 ( - 12 )} : - \frac{7}{4}

x = \frac{- ( - 1 ) - 41}{2 ( - 12 )} : \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{7}{4}, x = \frac{5}{3}

m (m - 6) = 0

- 8 x - 4 x^{2} = 14

4 (x + 5)^{2} = - 64

2 x^{2} + 4 x + 18 = 0

5^{2} + b^{2} = 1 2^{2}

What are the solutions to the equation 4x^2+6x+35=16x^2+7x ?
The solutions to the equation 4x^2+6x+35=16x^2+7x are x=-7/4 ,x= 5/3
Find the zeros of 4x^2+6x+35=16x^2+7x
The zeros of 4x^2+6x+35=16x^2+7x are x=-7/4 ,x= 5/3