What are the solutions to the equation completesquare z^2+z-3=0 ?

The solutions to the equation completesquare z^2+z-3=0 are z=(sqrt(13)-1)/2 ,z=(-sqrt(13)-1)/2

Find the zeros of completesquare z^2+z-3=0

The zeros of completesquare z^2+z-3=0 are z=(sqrt(13)-1)/2 ,z=(-sqrt(13)-1)/2

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z^{2} + z - 3 = 0

z = \frac{13 - 1}{2}, z = \frac{- 13 - 1}{2}

Decimal Notation

z = 1.30277 \dots, z = - 2.30277 \dots

Solution steps

z^{2} + z - 3 = 0

Move

3

to the right side

z^{2} + z = 3

Rewrite in the form

(x + a)^{2} = b

(z + \frac{1}{2})^{2} = \frac{13}{4}

For

the solutions are

f (x) = a, - a

Solve

z + \frac{1}{2} = \frac{13}{4} : z = \frac{13 - 1}{2}

Solve

z + \frac{1}{2} = - \frac{13}{4} : z = \frac{- 13 - 1}{2}

The solutions to the quadratic equation are:

z = \frac{13 - 1}{2}, z = \frac{- 13 - 1}{2}

3 x^{2} - 45 = 2 x^{2}

3 x = x^{2} - 2

9 x^{2} + 6 x = - 10

(x - 1) (3 x + 2) = 0

(11 x - 12)^{2} = 20

What are the solutions to the equation completesquare z^2+z-3=0 ?
The solutions to the equation completesquare z^2+z-3=0 are z=(sqrt(13)-1)/2 ,z=(-sqrt(13)-1)/2
Find the zeros of completesquare z^2+z-3=0
The zeros of completesquare z^2+z-3=0 are z=(sqrt(13)-1)/2 ,z=(-sqrt(13)-1)/2