What are the solutions to the equation 3x^2+6x-6=-2x^2 ?

The solutions to the equation 3x^2+6x-6=-2x^2 are x=(-3+sqrt(39))/5 ,x=-(3+sqrt(39))/5

Find the zeros of 3x^2+6x-6=-2x^2

The zeros of 3x^2+6x-6=-2x^2 are x=(-3+sqrt(39))/5 ,x=-(3+sqrt(39))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 6 x - 6 = - 2 x^{2}

x = \frac{- 3 + 39}{5}, x = - \frac{3 + 39}{5}

Decimal Notation

x = 0.64899 \dots, x = - 1.84899 \dots

Solution steps

3 x^{2} + 6 x - 6 = - 2 x^{2}

Move

2 x^{2}

to the left side

5 x^{2} + 6 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

6^{2} - 4 \cdot 5 (- 6) = 239

x_{1, 2} = \frac{- 6 \pm 2 39}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 2 39}{2 \cdot 5}, x_{2} = \frac{- 6 - 2 39}{2 \cdot 5}

x = \frac{- 6 + 2 39}{2 \cdot 5} : \frac{- 3 + 39}{5}

x = \frac{- 6 - 2 39}{2 \cdot 5} : - \frac{3 + 39}{5}

The solutions to the quadratic equation are:

x = \frac{- 3 + 39}{5}, x = - \frac{3 + 39}{5}

- 5 x^{2} + 101 x - 193 = 0

x^{2} - 18 x - 3 = 0

- 4 = (x - 3)^{2} - 4

2 x^{2} - 6 = - 206

(x + 1) (x - 2) = 3 (x - 2)

What are the solutions to the equation 3x^2+6x-6=-2x^2 ?
The solutions to the equation 3x^2+6x-6=-2x^2 are x=(-3+sqrt(39))/5 ,x=-(3+sqrt(39))/5
Find the zeros of 3x^2+6x-6=-2x^2
The zeros of 3x^2+6x-6=-2x^2 are x=(-3+sqrt(39))/5 ,x=-(3+sqrt(39))/5