What are the solutions to the equation 256=-x^2 ?

The solutions to the equation 256=-x^2 are x=16i,x=-16i

Find the zeros of 256=-x^2

The zeros of 256=-x^2 are x=16i,x=-16i

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256 = - x^{2}

x = 16 i, x = - 16 i

Solution steps

256 = - x^{2}

Switch sides

- x^{2} = 256

Divide both sides by

- 1

x^{2} = - 256

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 256, x = - - 256

- 256 = 16 i

- - 256 = - 16 i

x = 16 i, x = - 16 i

\frac{3 + x ^{2}}{7} = 4

5 x^{2} = 2 x + 1

x, n x^{2} - k x + 64 = 0

t (t) = 25 - 2 t, 0 \leq t \leq 10

1 0^{2} + 8^{2} = c^{2}

What are the solutions to the equation 256=-x^2 ?
The solutions to the equation 256=-x^2 are x=16i,x=-16i
Find the zeros of 256=-x^2
The zeros of 256=-x^2 are x=16i,x=-16i