What are the solutions to the equation factor t^2+3t+2=0 ?

The solutions to the equation factor t^2+3t+2=0 are t=-1,t=-2

Find the zeros of factor t^2+3t+2=0

The zeros of factor t^2+3t+2=0 are t=-1,t=-2

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t^{2} + 3 t + 2 = 0

t = - 1, t = - 2

Solution steps

t^{2} + 3 t + 2 = 0

Factor

t^{2} + 3 t + 2 : (t + 1) (t + 2)

(t + 1) (t + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t + 1 = 0 or t + 2 = 0

Solve

t + 1 = 0 : t = - 1

Solve

t + 2 = 0 : t = - 2

The solutions to the quadratic equation are:

t = - 1, t = - 2

(x - 1)^{2} = 14

\frac{1}{4} (2 x - 12)^{2} + 8 = 4

5 x - x^{2}

0.32 x^{2} - 1.2 x + 1 = 0

a x^{2} + (a + b) x + b = 0

What are the solutions to the equation factor t^2+3t+2=0 ?
The solutions to the equation factor t^2+3t+2=0 are t=-1,t=-2
Find the zeros of factor t^2+3t+2=0
The zeros of factor t^2+3t+2=0 are t=-1,t=-2