What are the solutions to the equation 4x(2-x)=0 ?

The solutions to the equation 4x(2-x)=0 are x=0,x=2

Find the zeros of 4x(2-x)=0

The zeros of 4x(2-x)=0 are x=0,x=2

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4 x (2 - x) = 0

x = 0, x = 2

Solution steps

4 x (2 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 - x = 0

Solve

2 - x = 0 : x = 2

The solutions to the quadratic equation are:

x = 0, x = 2

(5 x + 2) (x - 1) = 7 x

t^{2} + 3 t + 2 = 0

(x - 1)^{2} = 14

\frac{1}{4} (2 x - 12)^{2} + 8 = 4

5 x - x^{2}

What are the solutions to the equation 4x(2-x)=0 ?
The solutions to the equation 4x(2-x)=0 are x=0,x=2
Find the zeros of 4x(2-x)=0
The zeros of 4x(2-x)=0 are x=0,x=2