What are the solutions to the equation completesquare 5x-x^2 ?

The solutions to the equation completesquare 5x-x^2 are -(x-5/2)^2+25/4

Find the zeros of completesquare 5x-x^2

The zeros of completesquare 5x-x^2 are -(x-5/2)^2+25/4

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complete the square

5 x - x^{2}

- (x - \frac{5}{2})^{2} + \frac{25}{4}

Solution steps

5 x - x^{2}

Write in the standard form

a x^{2} + b x + c

- x^{2} + 5 x

Write

- x^{2} + 5 x

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 1

- (x^{2} - 5 x)

2 a = - 5 : a = - \frac{5}{2}

Add and subtract

(- \frac{5}{2})^{2}

- (x^{2} - 5 x + (- \frac{5}{2})^{2} - (- \frac{5}{2})^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 5 x + (- \frac{5}{2})^{2} = (x - \frac{5}{2})^{2}

- ((x - \frac{5}{2})^{2} - (- \frac{5}{2})^{2})

Simplify

- (x - \frac{5}{2})^{2} + \frac{25}{4}

0.32 x^{2} - 1.2 x + 1 = 0

a x^{2} + (a + b) x + b = 0

x + 3 = 39 - x^{2}

y = y (4 - y)

x^{2} - 10 x = - 22

What are the solutions to the equation completesquare 5x-x^2 ?
The solutions to the equation completesquare 5x-x^2 are -(x-5/2)^2+25/4
Find the zeros of completesquare 5x-x^2
The zeros of completesquare 5x-x^2 are -(x-5/2)^2+25/4