What are the solutions to the equation 4x^2+32x=-64 ?

The solutions to the equation 4x^2+32x=-64 are x=-4

Find the zeros of 4x^2+32x=-64

The zeros of 4x^2+32x=-64 are x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 32 x = - 64

x = - 4

Solution steps

4 x^{2} + 32 x = - 64

Move

64

to the left side

4 x^{2} + 32 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 4 \cdot 64}{2 \cdot 4}

3 2^{2} - 4 \cdot 4 \cdot 64 = 0

x_{1, 2} = \frac{- 32 \pm 0}{2 \cdot 4}

x = \frac{- 32}{2 \cdot 4}

\frac{- 32}{2 \cdot 4} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

- x^{2} + 10 x - 22 = 0

1 + x^{2} = (- 10)^{2}

3 x - 6 + 6 x^{2} = 0

0 = 210 + 264 t + 0.5 (- 32.2) t^{2}

0 = 3 x^{2} - x

What are the solutions to the equation 4x^2+32x=-64 ?
The solutions to the equation 4x^2+32x=-64 are x=-4
Find the zeros of 4x^2+32x=-64
The zeros of 4x^2+32x=-64 are x=-4