What are the solutions to the equation 3x-6+6x^2=0 ?

The solutions to the equation 3x-6+6x^2=0 are x=(-1+sqrt(17))/4 ,x=-(1+sqrt(17))/4

Find the zeros of 3x-6+6x^2=0

The zeros of 3x-6+6x^2=0 are x=(-1+sqrt(17))/4 ,x=-(1+sqrt(17))/4

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3 x - 6 + 6 x^{2} = 0

x = \frac{- 1 + 17}{4}, x = - \frac{1 + 17}{4}

Decimal Notation

x = 0.78077 \dots, x = - 1.28077 \dots

Solution steps

3 x - 6 + 6 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} + 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 6 ( - 6 )}{2 \cdot 6}

3^{2} - 4 \cdot 6 (- 6) = 317

x_{1, 2} = \frac{- 3 \pm 3 17}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 3 + 3 17}{2 \cdot 6}, x_{2} = \frac{- 3 - 3 17}{2 \cdot 6}

x = \frac{- 3 + 3 17}{2 \cdot 6} : \frac{- 1 + 17}{4}

x = \frac{- 3 - 3 17}{2 \cdot 6} : - \frac{1 + 17}{4}

The solutions to the quadratic equation are:

x = \frac{- 1 + 17}{4}, x = - \frac{1 + 17}{4}

0 = 210 + 264 t + 0.5 (- 32.2) t^{2}

0 = 3 x^{2} - x

- 49 x^{2} = 56

x^{2} + 6 x - 12 = 0

(x - \frac{3}{2})^{2} = 0

What are the solutions to the equation 3x-6+6x^2=0 ?
The solutions to the equation 3x-6+6x^2=0 are x=(-1+sqrt(17))/4 ,x=-(1+sqrt(17))/4
Find the zeros of 3x-6+6x^2=0
The zeros of 3x-6+6x^2=0 are x=(-1+sqrt(17))/4 ,x=-(1+sqrt(17))/4