What are the solutions to the equation 1+x^2=(-sqrt(10))^2 ?

The solutions to the equation 1+x^2=(-sqrt(10))^2 are x=3,x=-3

Find the zeros of 1+x^2=(-sqrt(10))^2

The zeros of 1+x^2=(-sqrt(10))^2 are x=3,x=-3

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1 + x^{2} = (- 10)^{2}

x = 3, x = - 3

Solution steps

1 + x^{2} = (- 10)^{2}

Expand

(- 10)^{2} : 10

1 + x^{2} = 10

Move

1

to the right side

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

3 x - 6 + 6 x^{2} = 0

0 = 210 + 264 t + 0.5 (- 32.2) t^{2}

0 = 3 x^{2} - x

- 49 x^{2} = 56

x^{2} + 6 x - 12 = 0

What are the solutions to the equation 1+x^2=(-sqrt(10))^2 ?
The solutions to the equation 1+x^2=(-sqrt(10))^2 are x=3,x=-3
Find the zeros of 1+x^2=(-sqrt(10))^2
The zeros of 1+x^2=(-sqrt(10))^2 are x=3,x=-3