What are the solutions to the equation factor 4x^2=5-8x ?

The solutions to the equation factor 4x^2=5-8x are x= 1/2 ,x=-5/2

Find the zeros of factor 4x^2=5-8x

The zeros of factor 4x^2=5-8x are x= 1/2 ,x=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} = 5 - 8 x

x = \frac{1}{2}, x = - \frac{5}{2}

Decimal Notation

x = 0.5, x = - 2.5

Solution steps

4 x^{2} = 5 - 8 x

Move

8 x

to the left side

4 x^{2} + 8 x = 5

Move

5

to the left side

4 x^{2} + 8 x - 5 = 0

Factor

4 x^{2} + 8 x - 5 : (2 x - 1) (2 x + 5)

(2 x - 1) (2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or 2 x + 5 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{5}{2}

3 x^{2} - 2 x + 12 = 0

9 x + 9 x^{2} - 4 = 0

(3 x + 5)^{2} = 0

6 x^{2} + 3 = - 11 x

5 y (2 y - 5) = 0

What are the solutions to the equation factor 4x^2=5-8x ?
The solutions to the equation factor 4x^2=5-8x are x= 1/2 ,x=-5/2
Find the zeros of factor 4x^2=5-8x
The zeros of factor 4x^2=5-8x are x= 1/2 ,x=-5/2