What are the solutions to the equation w^2+58=4 ?

The solutions to the equation w^2+58=4 are w=3sqrt(6)i,w=-3sqrt(6)i

Find the zeros of w^2+58=4

The zeros of w^2+58=4 are w=3sqrt(6)i,w=-3sqrt(6)i

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w^{2} + 58 = 4

w = 36 i, w = - 36 i

Solution steps

w^{2} + 58 = 4

Move

58

to the right side

w^{2} = - 54

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

w = - 54, w = - - 54

- 54 = 36 i

- - 54 = - 36 i

w = 36 i, w = - 36 i

x, 2 x y = x^{2} + y^{2}

3 x (4 - x) = 15

1890 = \frac{1}{10} x (300 - x)

x^{2} - 14 x - 31 = 0

3 x (x - 2) - x^{2} = (x - 3) (x + 5)

What are the solutions to the equation w^2+58=4 ?
The solutions to the equation w^2+58=4 are w=3sqrt(6)i,w=-3sqrt(6)i
Find the zeros of w^2+58=4
The zeros of w^2+58=4 are w=3sqrt(6)i,w=-3sqrt(6)i