What are the solutions to the equation (x+2)^2=17 ?

The solutions to the equation (x+2)^2=17 are x=sqrt(17)-2,x=-sqrt(17)-2

Find the zeros of (x+2)^2=17

The zeros of (x+2)^2=17 are x=sqrt(17)-2,x=-sqrt(17)-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 2)^{2} = 17

x = 17 - 2, x = - 17 - 2

Decimal Notation

x = 2.12310 \dots, x = - 6.12310 \dots

Solution steps

(x + 2)^{2} = 17

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 17 : x = 17 - 2

Solve

x + 2 = - 17 : x = - 17 - 2

The solutions to the quadratic equation are:

x = 17 - 2, x = - 17 - 2

4.9 x^{2} + 8 x - 30 = 0

(2 x + 2)^{2} - 12 = 4

u^{2} + 4 u + 3 = 0

- 3 x + x^{2} - 4 = - 8 + x

6 x (x - 1) = 63 - 19 x

What are the solutions to the equation (x+2)^2=17 ?
The solutions to the equation (x+2)^2=17 are x=sqrt(17)-2,x=-sqrt(17)-2
Find the zeros of (x+2)^2=17
The zeros of (x+2)^2=17 are x=sqrt(17)-2,x=-sqrt(17)-2