What are the solutions to the equation (p-2)(p-5)=3 ?

The solutions to the equation (p-2)(p-5)=3 are p=(7+sqrt(21))/2 ,p=(7-sqrt(21))/2

Find the zeros of (p-2)(p-5)=3

The zeros of (p-2)(p-5)=3 are p=(7+sqrt(21))/2 ,p=(7-sqrt(21))/2

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(p - 2) (p - 5) = 3

p = \frac{7 + 21}{2}, p = \frac{7 - 21}{2}

Decimal Notation

p = 5.79128 \dots, p = 1.20871 \dots

Solution steps

(p - 2) (p - 5) = 3

Expand

(p - 2) (p - 5) : p^{2} - 7 p + 10

p^{2} - 7 p + 10 = 3

Move

3

to the left side

p^{2} - 7 p + 7 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 7 = 21

p_{1, 2} = \frac{- ( - 7 ) \pm 21}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 7 ) + 21}{2 \cdot 1}, p_{2} = \frac{- ( - 7 ) - 21}{2 \cdot 1}

p = \frac{- ( - 7 ) + 21}{2 \cdot 1} : \frac{7 + 21}{2}

p = \frac{- ( - 7 ) - 21}{2 \cdot 1} : \frac{7 - 21}{2}

The solutions to the quadratic equation are:

p = \frac{7 + 21}{2}, p = \frac{7 - 21}{2}

(x + 2)^{2} = 17

4.9 x^{2} + 8 x - 30 = 0

(2 x + 2)^{2} - 12 = 4

u^{2} + 4 u + 3 = 0

- 3 x + x^{2} - 4 = - 8 + x

What are the solutions to the equation (p-2)(p-5)=3 ?
The solutions to the equation (p-2)(p-5)=3 are p=(7+sqrt(21))/2 ,p=(7-sqrt(21))/2
Find the zeros of (p-2)(p-5)=3
The zeros of (p-2)(p-5)=3 are p=(7+sqrt(21))/2 ,p=(7-sqrt(21))/2