What are the solutions to the equation (2x+2)^2-12=4 ?

The solutions to the equation (2x+2)^2-12=4 are x=1,x=-3

Find the zeros of (2x+2)^2-12=4

The zeros of (2x+2)^2-12=4 are x=1,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x + 2)^{2} - 12 = 4

x = 1, x = - 3

Solution steps

(2 x + 2)^{2} - 12 = 4

Move

12

to the right side

(2 x + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 2 = 16 : x = 1

Solve

2 x + 2 = - 16 : x = - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

u^{2} + 4 u + 3 = 0

- 3 x + x^{2} - 4 = - 8 + x

6 x (x - 1) = 63 - 19 x

6 x^{2} - x - 15 = 0

(x - 9) (x + 7) = 1

What are the solutions to the equation (2x+2)^2-12=4 ?
The solutions to the equation (2x+2)^2-12=4 are x=1,x=-3
Find the zeros of (2x+2)^2-12=4
The zeros of (2x+2)^2-12=4 are x=1,x=-3