What are the solutions to the equation solvefor x,y=(x+1)^2 ?

The solutions to the equation solvefor x,y=(x+1)^2 are x=sqrt(y)-1,x=-sqrt(y)-1

Find the zeros of solvefor x,y=(x+1)^2

The zeros of solvefor x,y=(x+1)^2 are x=sqrt(y)-1,x=-sqrt(y)-1

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solve for

x, y = (x + 1)^{2}

x = y - 1, x = - y - 1

Solution steps

y = (x + 1)^{2}

Switch sides

(x + 1)^{2} = y

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = y : x = y - 1

Solve

x + 1 = - y : x = - y - 1

The solutions to the quadratic equation are:

x = y - 1, x = - y - 1

3 x^{2} + 19 x - 6 = 0

16 x^{2} + 6 x - 1 = 0

7 x^{2} - 11 x - 12 = 0

2 x^{2} - 5 x - 21 = 0

x, x^{2} + 7 x - 2 = 0

What are the solutions to the equation solvefor x,y=(x+1)^2 ?
The solutions to the equation solvefor x,y=(x+1)^2 are x=sqrt(y)-1,x=-sqrt(y)-1
Find the zeros of solvefor x,y=(x+1)^2
The zeros of solvefor x,y=(x+1)^2 are x=sqrt(y)-1,x=-sqrt(y)-1