What are the solutions to the equation x^2+12^2=18^2 ?

The solutions to the equation x^2+12^2=18^2 are x=6sqrt(5),x=-6sqrt(5)

Find the zeros of x^2+12^2=18^2

The zeros of x^2+12^2=18^2 are x=6sqrt(5),x=-6sqrt(5)

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x^{2} + 1 2^{2} = 1 8^{2}

x = 65, x = - 65

Decimal Notation

x = 13.41640 \dots, x = - 13.41640 \dots

Solution steps

x^{2} + 1 2^{2} = 1 8^{2}

Move

1 2^{2}

to the right side

x^{2} = 180

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 180, x = - 180

180 = 65

- 180 = - 65

x = 65, x = - 65

2 (x - 3)^{2} - 40 = 0

- x^{2} + 2 x - 3

y, x = z^{2} + y^{2}

2 s^{2} - 5 s = 3

3 x^{2} + 3 x = 2 x - 1

What are the solutions to the equation x^2+12^2=18^2 ?
The solutions to the equation x^2+12^2=18^2 are x=6sqrt(5),x=-6sqrt(5)
Find the zeros of x^2+12^2=18^2
The zeros of x^2+12^2=18^2 are x=6sqrt(5),x=-6sqrt(5)