What are the solutions to the equation solvefor w,z=-2w^2 ?

The solutions to the equation solvefor w,z=-2w^2 are w=isqrt(z/2),w=-isqrt(z/2)

Find the zeros of solvefor w,z=-2w^2

The zeros of solvefor w,z=-2w^2 are w=isqrt(z/2),w=-isqrt(z/2)

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solve for

w, z = - 2 w^{2}

w = i \frac{z}{2}, w = - i \frac{z}{2}

Solution steps

z = - 2 w^{2}

Switch sides

- 2 w^{2} = z

Divide both sides by

- 2

w^{2} = - \frac{z}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

w = - \frac{z}{2}, w = - - \frac{z}{2}

Simplify

- \frac{z}{2} : i \frac{z}{2}

Simplify

- - \frac{z}{2} : - i \frac{z}{2}

w = i \frac{z}{2}, w = - i \frac{z}{2}

(x + 1)^{3} = (x + 2)^{3} - 1

x^{2} + 3 x = 20 x

6 - \frac{x ^{2}}{4} = 2

p^{2} + 16 p - 22 = 0

3 x (x - 2) = 9 x^{2} - 7 x

What are the solutions to the equation solvefor w,z=-2w^2 ?
The solutions to the equation solvefor w,z=-2w^2 are w=isqrt(z/2),w=-isqrt(z/2)
Find the zeros of solvefor w,z=-2w^2
The zeros of solvefor w,z=-2w^2 are w=isqrt(z/2),w=-isqrt(z/2)