What are the solutions to the equation solvefor x,x^2-2x=m^2+2m ?

The solutions to the equation solvefor x,x^2-2x=m^2+2m are x=-m,x=m+2

Find the zeros of solvefor x,x^2-2x=m^2+2m

The zeros of solvefor x,x^2-2x=m^2+2m are x=-m,x=m+2

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x, x^{2} - 2 x = m^{2} + 2 m

x = - m, x = m + 2

Solution steps

x^{2} - 2 x = m^{2} + 2 m

Move

2 m

to the left side

x^{2} - 2 x - 2 m = m^{2}

Move

m^{2}

to the left side

x^{2} - 2 x - 2 m - m^{2} = 0

Factor

x^{2} - 2 x - 2 m - m^{2} : (x + m) (x - m - 2)

(x + m) (x - m - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + m = 0 or x - m - 2 = 0

Solve

x + m = 0 : x = - m

Solve

x - m - 2 = 0 : x = m + 2

The solutions to the quadratic equation are:

x = - m, x = m + 2

- 3 x^{2} + (7 k^{2} - 3) x + 7 = 0

w, z = - 2 w^{2}

(x + 1)^{3} = (x + 2)^{3} - 1

x^{2} + 3 x = 20 x

6 - \frac{x ^{2}}{4} = 2

What are the solutions to the equation solvefor x,x^2-2x=m^2+2m ?
The solutions to the equation solvefor x,x^2-2x=m^2+2m are x=-m,x=m+2
Find the zeros of solvefor x,x^2-2x=m^2+2m
The zeros of solvefor x,x^2-2x=m^2+2m are x=-m,x=m+2