What are the solutions to the equation x^2-3x-6=2x+30 ?

The solutions to the equation x^2-3x-6=2x+30 are x=9,x=-4

Find the zeros of x^2-3x-6=2x+30

The zeros of x^2-3x-6=2x+30 are x=9,x=-4

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x^{2} - 3 x - 6 = 2 x + 30

x = 9, x = - 4

Solution steps

x^{2} - 3 x - 6 = 2 x + 30

Move

30

to the left side

x^{2} - 3 x - 36 = 2 x

Move

2 x

to the left side

x^{2} - 5 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 36) = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 1}

x = \frac{- ( - 5 ) + 13}{2 \cdot 1} : 9

x = \frac{- ( - 5 ) - 13}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 9, x = - 4

x, x^{2} + 4 x - 8 = 0

X^{2} + 3 X + 1 = 0

4 y^{2} + 20 y - 11 = 0

- 6 - 2 r^{2} = - 26

2 x^{2} = 4 x - 6

What are the solutions to the equation x^2-3x-6=2x+30 ?
The solutions to the equation x^2-3x-6=2x+30 are x=9,x=-4
Find the zeros of x^2-3x-6=2x+30
The zeros of x^2-3x-6=2x+30 are x=9,x=-4