What are the solutions to the equation (7x+5)^2+7(7x+5)=0 ?

The solutions to the equation (7x+5)^2+7(7x+5)=0 are x=-5/7 ,x=-12/7

Find the zeros of (7x+5)^2+7(7x+5)=0

The zeros of (7x+5)^2+7(7x+5)=0 are x=-5/7 ,x=-12/7

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(7 x + 5)^{2} + 7 (7 x + 5) = 0

x = - \frac{5}{7}, x = - \frac{12}{7}

Solution steps

(7 x + 5)^{2} + 7 (7 x + 5) = 0

Expand

(7 x + 5)^{2} + 7 (7 x + 5) : 49 x^{2} + 119 x + 60

49 x^{2} + 119 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 119 \pm 11 9 ^{2} - 4 \cdot 49 \cdot 60}{2 \cdot 49}

11 9^{2} - 4 \cdot 49 \cdot 60 = 49

x_{1, 2} = \frac{- 119 \pm 49}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- 119 + 49}{2 \cdot 49}, x_{2} = \frac{- 119 - 49}{2 \cdot 49}

x = \frac{- 119 + 49}{2 \cdot 49} : - \frac{5}{7}

x = \frac{- 119 - 49}{2 \cdot 49} : - \frac{12}{7}

The solutions to the quadratic equation are:

x = - \frac{5}{7}, x = - \frac{12}{7}

x^{2} - 3 x - 6 = 2 x + 30

x, x^{2} + 4 x - 8 = 0

X^{2} + 3 X + 1 = 0

4 y^{2} + 20 y - 11 = 0

- 6 - 2 r^{2} = - 26

What are the solutions to the equation (7x+5)^2+7(7x+5)=0 ?
The solutions to the equation (7x+5)^2+7(7x+5)=0 are x=-5/7 ,x=-12/7
Find the zeros of (7x+5)^2+7(7x+5)=0
The zeros of (7x+5)^2+7(7x+5)=0 are x=-5/7 ,x=-12/7