What are the solutions to the equation X^2+3X+1=0 ?

The solutions to the equation X^2+3X+1=0 are X=(-3+sqrt(5))/2 ,X=(-3-sqrt(5))/2

Find the zeros of X^2+3X+1=0

The zeros of X^2+3X+1=0 are X=(-3+sqrt(5))/2 ,X=(-3-sqrt(5))/2

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X^{2} + 3 X + 1 = 0

X = \frac{- 3 + 5}{2}, X = \frac{- 3 - 5}{2}

Decimal Notation

X = - 0.38196 \dots, X = - 2.61803 \dots

Solution steps

X^{2} + 3 X + 1 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 1 = 5

X_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 3 + 5}{2 \cdot 1}, X_{2} = \frac{- 3 - 5}{2 \cdot 1}

X = \frac{- 3 + 5}{2 \cdot 1} : \frac{- 3 + 5}{2}

X = \frac{- 3 - 5}{2 \cdot 1} : \frac{- 3 - 5}{2}

The solutions to the quadratic equation are:

X = \frac{- 3 + 5}{2}, X = \frac{- 3 - 5}{2}

4 y^{2} + 20 y - 11 = 0

- 6 - 2 r^{2} = - 26

2 x^{2} = 4 x - 6

1 - x^{2} = 0

5 (x + 3)^{2} - 7 = 68

What are the solutions to the equation X^2+3X+1=0 ?
The solutions to the equation X^2+3X+1=0 are X=(-3+sqrt(5))/2 ,X=(-3-sqrt(5))/2
Find the zeros of X^2+3X+1=0
The zeros of X^2+3X+1=0 are X=(-3+sqrt(5))/2 ,X=(-3-sqrt(5))/2