What are the solutions to the equation -6-2r^2=-26 ?

The solutions to the equation -6-2r^2=-26 are r=sqrt(10),r=-sqrt(10)

Find the zeros of -6-2r^2=-26

The zeros of -6-2r^2=-26 are r=sqrt(10),r=-sqrt(10)

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- 6 - 2 r^{2} = - 26

r = 10, r = - 10

Solution steps

- 6 - 2 r^{2} = - 26

Move

6

to the right side

- 2 r^{2} = - 20

Divide both sides by

- 2

r^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 10, r = - 10

2 x^{2} = 4 x - 6

1 - x^{2} = 0

5 (x + 3)^{2} - 7 = 68

4 x (x - 1) = 3

t, f = 2 t - 3 f (t^{2})

What are the solutions to the equation -6-2r^2=-26 ?
The solutions to the equation -6-2r^2=-26 are r=sqrt(10),r=-sqrt(10)
Find the zeros of -6-2r^2=-26
The zeros of -6-2r^2=-26 are r=sqrt(10),r=-sqrt(10)