What are the solutions to the equation (x-6)(x-8)=-1 ?

The solutions to the equation (x-6)(x-8)=-1 are x=7

Find the zeros of (x-6)(x-8)=-1

The zeros of (x-6)(x-8)=-1 are x=7

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(x - 6) (x - 8) = - 1

x = 7

Solution steps

(x - 6) (x - 8) = - 1

Expand

(x - 6) (x - 8) : x^{2} - 14 x + 48

x^{2} - 14 x + 48 = - 1

Move

1

to the left side

x^{2} - 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 14 )}{2 \cdot 1}

\frac{- ( - 14 )}{2 \cdot 1} = 7

x = 7

The solution to the quadratic equation is:

x = 7

- 3 x^{2} - 18 x - 26 = 0

0.2 x^{2} - 6 x + 80 = 0.6 x^{2} - 12 x + 80

a, c = ba + a^{2}

- 2 x^{2} + 12 x - 8 = 0

(3 x + 2)^{2} - 5 (3 x + 2) = 0

What are the solutions to the equation (x-6)(x-8)=-1 ?
The solutions to the equation (x-6)(x-8)=-1 are x=7
Find the zeros of (x-6)(x-8)=-1
The zeros of (x-6)(x-8)=-1 are x=7