What are the solutions to the equation -3x^2-18x-26=0 ?

The solutions to the equation -3x^2-18x-26=0 are x=-(9+sqrt(3))/3 ,x=-(9-sqrt(3))/3

Find the zeros of -3x^2-18x-26=0

The zeros of -3x^2-18x-26=0 are x=-(9+sqrt(3))/3 ,x=-(9-sqrt(3))/3

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- 3 x^{2} - 18 x - 26 = 0

x = - \frac{9 + 3}{3}, x = - \frac{9 - 3}{3}

Solution steps

- 3 x^{2} - 18 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 ( - 3 ) ( - 26 )}{2 ( - 3 )}

(- 18)^{2} - 4 (- 3) (- 26) = 23

x_{1, 2} = \frac{- ( - 18 ) \pm 2 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 3}{2 ( - 3 )}, x_{2} = \frac{- ( - 18 ) - 2 3}{2 ( - 3 )}

x = \frac{- ( - 18 ) + 2 3}{2 ( - 3 )} : - \frac{9 + 3}{3}

x = \frac{- ( - 18 ) - 2 3}{2 ( - 3 )} : - \frac{9 - 3}{3}

The solutions to the quadratic equation are:

x = - \frac{9 + 3}{3}, x = - \frac{9 - 3}{3}

0.2 x^{2} - 6 x + 80 = 0.6 x^{2} - 12 x + 80

a, c = ba + a^{2}

- 2 x^{2} + 12 x - 8 = 0

(3 x + 2)^{2} - 5 (3 x + 2) = 0

b^{2} + 3 b - 10 = 0

What are the solutions to the equation -3x^2-18x-26=0 ?
The solutions to the equation -3x^2-18x-26=0 are x=-(9+sqrt(3))/3 ,x=-(9-sqrt(3))/3
Find the zeros of -3x^2-18x-26=0
The zeros of -3x^2-18x-26=0 are x=-(9+sqrt(3))/3 ,x=-(9-sqrt(3))/3