What are the solutions to the equation -2x^2+12x-8=0 ?

The solutions to the equation -2x^2+12x-8=0 are x=3-sqrt(5),x=3+sqrt(5)

Find the zeros of -2x^2+12x-8=0

The zeros of -2x^2+12x-8=0 are x=3-sqrt(5),x=3+sqrt(5)

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- 2 x^{2} + 12 x - 8 = 0

x = 3 - 5, x = 3 + 5

Decimal Notation

x = 0.76393 \dots, x = 5.23606 \dots

Solution steps

- 2 x^{2} + 12 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 2 ) ( - 8 )}{2 ( - 2 )}

1 2^{2} - 4 (- 2) (- 8) = 45

x_{1, 2} = \frac{- 12 \pm 4 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 12 + 4 5}{2 ( - 2 )}, x_{2} = \frac{- 12 - 4 5}{2 ( - 2 )}

x = \frac{- 12 + 4 5}{2 ( - 2 )} : 3 - 5

x = \frac{- 12 - 4 5}{2 ( - 2 )} : 3 + 5

The solutions to the quadratic equation are:

x = 3 - 5, x = 3 + 5

2 x^{2} + 7 x + 3 = 0

(3 x + 2)^{2} - 5 (3 x + 2) = 0

b^{2} + 3 b - 10 = 0

- 16 x^{2} + 32 x = 0

37 n^{2} + 42 n - 20 = - 12 n^{2} + 7

What are the solutions to the equation -2x^2+12x-8=0 ?
The solutions to the equation -2x^2+12x-8=0 are x=3-sqrt(5),x=3+sqrt(5)
Find the zeros of -2x^2+12x-8=0
The zeros of -2x^2+12x-8=0 are x=3-sqrt(5),x=3+sqrt(5)