What are the solutions to the equation b^2+3b-10=0 ?

The solutions to the equation b^2+3b-10=0 are b=2,b=-5

Find the zeros of b^2+3b-10=0

The zeros of b^2+3b-10=0 are b=2,b=-5

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b^{2} + 3 b - 10 = 0

b = 2, b = - 5

Solution steps

b^{2} + 3 b - 10 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 10) = 7

b_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- 3 + 7}{2 \cdot 1}, b_{2} = \frac{- 3 - 7}{2 \cdot 1}

b = \frac{- 3 + 7}{2 \cdot 1} : 2

b = \frac{- 3 - 7}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

b = 2, b = - 5

- 16 x^{2} + 32 x = 0

37 n^{2} + 42 n - 20 = - 12 n^{2} + 7

x (x + 1) = 4 - (x + 2)^{2}

3 x^{2} + 24 x + 32 = 0

x, 2 x^{2} y = 5

What are the solutions to the equation b^2+3b-10=0 ?
The solutions to the equation b^2+3b-10=0 are b=2,b=-5
Find the zeros of b^2+3b-10=0
The zeros of b^2+3b-10=0 are b=2,b=-5